In the givenv-t graph, the distance travelled by the body in 5 second

1.	In the givenv-t graph, the distance travelled by the body in 5 second will be .
Answer» Solution :For the give velociyt-position graph, intercept`= v_0 ` and slope `=- v_0//x-0` The equation of given LINE is , ` v=- v_0/x_0 x = v_0` Differentiatng it w.tr.t. t, we have ` (dv)/(DT)=- v-0/x_0 (DX)/(dt)` or ` a=- v_0 /x_0 v` ` =- v-0 /x_0 ( - v_0/x_0 x + v_0 ) = v_0^2/x_0^2 x - v_0^@/x_0` It is an equation of straight line between (a) and (x) with positive slope ` (=(v_0^2)/x_0^20` and NEGATIVE intercept ` ( = - ( v_0^2/x_0)`.

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