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In the HCl molecule, the separation between the nuclei of two atoms is about 1.27 A (1 A = 10^(-10)m). Find the approximate location of the CM. of the molecule, given that a chlorine atom is about 35.5 times as massive as a hydrogen atom and nearly all the mass of an atom is concentrated in its nucleus. |
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Answer» Solution :HYDROGEN ATOM is assumed to be at the origin `x_(1) = 0, m _(1)=m, x_(2) = 1.27A` `=1.27 XX 10^(-10) m` `m_(2) = 35.5` m The POSITION of centre of mass `x=(m_(1)x_(1) + m_(2)x_(2))/(m_(1) + m_(2)) = (m xx 0 + 35.5 m xx 1.27 xx 10^(-10))/(m + 35.5 m)` `=(45.08 xx 10^(-10)m)/(36.5 m) = (45.08 xx 10^(-10))/(36.5) = (45.08 xx 10^(-10))/(36.5)` `=1.24 xx 10^(-10)` m |
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