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In the ideal atwood machine arrangement shown, what is the change in kinetic energy of the system in `(1)/(sqrt2)`second of their motion starting from rest ? A. `1J`B. `2J`C. `4J`D. `5J` |
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Answer» Correct Answer - D Acceleration`=(3g-2g)/(5)=2m//s^(2)` so `v=2xx(1)/(sqrt2)=sqrt2m//s` `:.DeltaE=(1)/(2)(2)(sqrt2)^(2)+(1)/(2)(3)(sqrt2)^(2)=5` |
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