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In the ideal double-slit experiment, when a glass-plate(refractive index 1.5) of thickness t is introduced in the path of one of the interfering beams (wave-length `lamda`), the intensity at the position where the central maximum occurred previously remains unchanged. The minimum thickness of the glass-plate isA. `2lamda`B. `(2lamda)/(3)`C. `(lamda)/(3)`D. `lamda` |
Answer» Correct Answer - A As path difference due to slab `=(mu-1)t` `implies(mu-1)t=nlamda` for munimum thickness t of plate, n should be minimum i.e. `n=1therefore(mu-1)t=lamda` `impliest=(lamda)/(mu-1)impliest=(lamda)/(1.5-1)impliest=2lamda` |
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