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In the ideal double-slit experiment, when a glass-plate (refractive index 1.5) of thickness t is introduced in the path of one of the interfering beams (wavelength `lambda`), the intensity at the position where the central maximum occurred previously remains unchanged. The minimum thickness of the glass-plate isA. (a) `2lambda`B. (b) `(2lambda)/(3)`C. (c) `lambda/3`D. (d) `lambda` |
Answer» Correct Answer - A According to given condition `(mu-1)t=nlambda` for minimum t, `n=1` So, `(mu-1)t_(min)=lambda` `t_(min)=(lambda)/(mu-1)=(lambda)/(1.5-1)=2lambda` |
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