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In the low-pass filter shown in the figure, for a cut-off frequency of 5kHz, the value of R2(in kΩ) is ____________. |
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Answer» f = 5KHz Cut off frequency (LPF) = 18/2πR2C = 5KHz ⇒ R2 = 1/(2π x 5 x 103 x 10 x 10-9) = 3.18kΩ |
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