1.

In the low-pass filter shown in the figure, for a cut-off frequency of 5kHz, the value of R2(in kΩ) is ____________. 

Answer»

f = 5KHz

Cut off frequency (LPF) = 18/2πR2C = 5KHz

⇒ R2 = 1/(2π x 5 x 103 x 10 x 10-9) = 3.18kΩ



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