In the mixture of NaHCO_(3) and NaCO_(3), volume of a given HCl required is x ml with phenolphathalein indicator and further y mL is required with methyl orange indicator. Hence volume of HCl for complete reaction of NaHCO_(3) present in the original mixture is

In the mixture of NaHCO_(3) and NaCO_(3), volume of a given HCl requir

1.	In the mixture of NaHCO_(3) and NaCO_(3), volume of a given HCl required is x ml with phenolphathalein indicator and further y mL is required with methyl orange indicator. Hence volume of HCl for complete reaction of NaHCO_(3) present in the original mixture is
Answer» 2x y `x//2` `(y-x)` Solution :In presence of phenolchalein photacium EQ. o HCL = `(1)/(2)` Eq `NC_(2)CO_(3)` `XxxN=(1)/(2)` eq `NO_(2)CO_(3)` In presence of methyl orange Eq. of `HCl=(1)/(2)` Eq `NO_(2)CO_(3)+` Eq `NaHCO_(3)` `yxxN=xN+` Eq `NaHCO_(3)` `THEREFORE` Eq `NaHCO_(3)` = `(y-x)xxN` Here `(y-x)` is the volume of HCl