In the molecule O_(A) = C = O_(B), the formal charge on O_(A), C and O_(B) are respectively.

In the molecule O_(A) = C = O_(B), the formal charge on O_(A), C and O

1.	In the molecule O_(A) = C = O_(B), the formal charge on O_(A), C and O_(B) are respectively.
Answer» `-1, 0, +1` `+1, 0, -1` `-2, 0, +2` 0, 0, 0 Solution : Formal charge of `O_(A)//O_(B) = N_(V) - (N_(e ) + (N_(b))/(2)) =6-(4 + (4)/(2)) =6-6=0` Formal charge of `C=4 -(0 +(8)/(2)) =4-4=0`