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In the Network shown in figure, C1 = 6 μF and C = 9μF. The equivalent capacitance between points P and Q is(a) 3 μF (b) 6 μF(c) 9 μF (d) 12 μF |
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Answer» Correct Option (a) 3 μF Explanation The last three capacitors on teh right. Each of capacitance C = μF are in series and are equivalent to a capacitance C' given by 1/C' = 1/9+1/9+1/9 = 1/3 or C' = 3μF Since C' is in parallel with C1, the equivalent capacitance of the last part of the network is C" = C' + C1 = 3 + 6 = 9 μF. |
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