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In the neutralization of `Na_(2)S_(2)O_(3)` using `K_(2)Cr_(2)O_(7)` by idometry, the equivalent weight of `K_(2)Cr_(2)O_(7)` isA. (molecular weight)/2B. (molecular weight)/6C. (molecular weight)/3D. same as molecular weight |
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Answer» Correct Answer - B The following reaction occur between `S_(2)O_(3)^(2-)` and `Cr_(2)O_(7)^(2-)` `26H^(+) + 3S_(2)O_(3)^(2-) + 4Cr_(2)O_(7)^(2-) rarr 6SO_(4)^(2-) + 8Cr^(3+) +13 H_(2)O` Change in oxidation number of `Cr_(2)O_(7)^(2-)` per formula unit is 6 (it is always fixed for `Cr_(2)O_(7)^(2-)`). Hence, equivalent weight of `K_(2)Cr_(2)O_(7) = ("Molecular weight")/(6)` |
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