1.

In the non-relativistic regime, if the momentum, is increased by 100%, the percentage increase in kinetic energy is

Answer»

100% 
200% 
3
400% 

SOLUTION :Kinetic energy , `K = (p^2)/(2m)`
Since m REMAINS costant , so `K PROP p^2`
`:. (K_1)/(K_2) = ((p_1)/(p_2))^(2) = 1/4" or " K_2 = 4K_1`
Percentage increase in kinetic energy = `(K_2 - K_1)/(K_1) xx 100%`
`= (4K_1 - K_1)/(K_1) xx 100% = 300%`.


Discussion

No Comment Found