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In the non-relativistic regime, if the momentum, is increased by 100%, the percentage increase in kinetic energy is |
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Answer» 100% Since m REMAINS costant , so `K PROP p^2` `:. (K_1)/(K_2) = ((p_1)/(p_2))^(2) = 1/4" or " K_2 = 4K_1` Percentage increase in kinetic energy = `(K_2 - K_1)/(K_1) xx 100%` `= (4K_1 - K_1)/(K_1) xx 100% = 300%`. |
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