In the nth orbit, the energy of an electron `E_(n)= -( 13.6)/(n^(2)) e – InterviewSolution

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1.	In the nth orbit, the energy of an electron `E_(n)= -( 13.6)/(n^(2)) eV` for hydrogen atom. The energy rquired to take the electron from first orbit to second orbit will beA. `10. 2 eV`B. `12.1 eV`C. `13.6 eV`D. `3.4 eV`
Answer» Correct Answer - A For n=2, using, `E_(n)=(-13.6eV)/(n^(2))E_(2)=-(13.6)/((2)^(2))=-3.4 eV` For n=1,`E_(1)=-13.6 eV` `:. " " E_(1rarr2)=-3.4-(-13.6)=10.2ev`

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