Saved Bookmarks
| 1. |
In the obsence of wind the range and maximum height of a projectile were R and H. If wind imparts a horizontal acceleration a = g/4 to the projectile then find the maximum range and maximum height. |
|
Answer» Solution :`H^(1) = H(:. u sin theta "REMAINS same"), T^(1) = T` `R^(1) = u_(x) T + (1)/(2)a T^(2) = R+(1)/(2)(g)/(4)T^(2) = R+(1)/(8) gT^(2) = R+H`
|
|