In the pervious question (6), the magnitude of the momentum transferre

1.	In the pervious question (6), the magnitude of the momentum transferred during the hit is
Answer» ZERO `0.75 kg -MS^(-1)` `1.5 kg ms^(-1)` `14 kg ms^(-1)` Solution :(b) By previous solution `Deltap=-(0.9hati+1.2hatj)` Magnitude =`\|Deltap\|=sqrt((0.9)^(2)+(1.2)^(2))` `=sqrt(0.81+1.44)=1.5 kg ms^(-1)`

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