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InterviewSolution
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In the picture, the square on the hypotenuse of the top most right triangle is drawn. Calculate the area and the length of a side of the square. |
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Answer» Hypotenuse of first right triangle \(\sqrt{1^2+1^2}=\sqrt{1+1}=\sqrt{2}\) Hypotenuse of second right triangle \(\sqrt{\sqrt{2^2}+1^2}=\sqrt{2+1}=\sqrt{3}\) Hypotenuse of third right triangle \(\sqrt{\sqrt{3^2}+1^2}=\sqrt{3+1}=\sqrt{4}=2\) Hypotenuse of fourth right triangle \(\sqrt{2^2+1^2}=\sqrt{4+1}=\sqrt{5}\) i. e. the length of one side of square is \(\sqrt{5}\) Area \(\sqrt{5}\times\sqrt{5}\) = 5 sq. m |
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