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In the polynomial x2 + kx + 6, what number must be taken ask to get a polynomial for which x –1 is a factor? Find also the other factor of that polynomial. |
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Answer» p (x) = x2 + kx + 6 If (x – 1) is a factor of p(x) then p(1) = 0 p(1) = 12 + k x 1 + 6 = 7 + k 7 + k = 0 k= –7 \(\therefore\) p(x) = x2 – 7x + 6 a + b = 7 ab = 6 a= 1, b = 6 factors are (x – 1 )(x – 6) Second factor is (x – 6) |
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