In the preparation of CaO from CaCO_(3) using the equilibrium CaCO_(3) (s) hArr CaO (s) + CO_(2) (g) , K_(p)is expressed as : log K_(p) = 7. 282 - 8500/TFor the complete decomposition of CaCO_(3), the temperature in Celsius to be used is

In the preparation of CaO from CaCO_(3) using the equilibrium CaCO_(3

1.	In the preparation of CaO from CaCO_(3) using the equilibrium CaCO_(3) (s) hArr CaO (s) + CO_(2) (g) , K_(p)is expressed as : log K_(p) = 7. 282 - 8500/TFor the complete decomposition of CaCO_(3), the temperature in Celsius to be used is
Answer» <P>1167 894 8500 850 Solution :For decomposition , `K_(p) = 1.` ` :. Log 1 = 7.282 - 8500/ T` i.e., `7.282 = 8500/T (log 1 = 0 ) ` or `T = (8500)/(7.282) = 1167 K` `= 1167 - 273 ^(@) C = 894 ^(@)C.`