In the previous problem (3), the magnitude of the momentum transferred

1.	In the previous problem (3), the magnitude of the momentum transferred during the hit is
Answer» <P>zero 0.75 KG `-ms^(-1)` 1.5 kg `-ms^(-1)` 14 kg `-ms^(-1)` Solution :`1.5 kg- m s^(-1)` As provedin ABOVESOLUTION `Delta p =-[ 0.9 HAT(j )+ 1.2 hat(j )]` Magnitude=`\|Delta p \|= sqrt ((0.9)^(2) + (1.2)^(2))` `= 1.5kg m//s`

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