1.

In the previous problem 3 the magnitude of the momentum transferred during the hit is .

Answer»

<P>zero
`0.75"KGMS"^(-1)`
`1.5"kgms"^(-1)`
`14"kgms"^(-1)`

Solution :The magnitude of the MOMENTUM TRANSFERRED during the HIT is
`|Deltabar(p)|=sqrt((-0.9)^(2)+(-1.2)^(2))kgms^(-1)`
`=sqrt(0.81+1.44)kgms^(-1)=1.5 kgms^(-1)`


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