In the previous problem if `M=80kg` and `m=410kg` and the boy pulls the rope such that the system (boy+box) moves upward with acceleration `5m//s^(2)`,find the force exerted by the boy and contact force between the boy and the box.

In the previous problem if `M=80kg` and `m=410kg` and the boy pulls th

1.	In the previous problem if `M=80kg` and `m=410kg` and the boy pulls the rope such that the system (boy+box) moves upward with acceleration `5m//s^(2)`,find the force exerted by the boy and contact force between the boy and the box.
Answer» Boy `:` `N_(0)-Mg=Ma` `rArrT+N_(0)=M(g+a)=80(10+5)=1200` (i) Box `:` `T-N_(0)-mg=ma` `rArrT-N_(0)=m(g+a)=40(10+5)=600` (ii) `T=900N,N_(0)=300N`

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In the previous problem if `M=80kg` and `m=410kg` and the boy pulls the rope such that the system (boy+box) moves upward with acceleration `5m//s^(2)`,find the force exerted by the boy and contact force between the boy and the box.

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