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In the problem what force should the man exert on the rope to get his correct weight on the machine ? |
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Answer» Solution :`T-cancel(M)G+cancel(M)g=Ma` `(because R=MG)a=(T)/(M)` `T-Mg-mg=ma` `T-m(T)/(M)=(m+M)g` `T=((m+M)Mg)/(M-m)=((30+60)60XX10)/(60-30)` `= (""^(3)cancel(90)XX600)/(cancel(30))=1800N`
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