1.

In the problem what force should the man exert on the rope to get his correct weight on the machine ?

Answer»

Solution :`T-cancel(M)G+cancel(M)g=Ma`
`(because R=MG)a=(T)/(M)`
`T-Mg-mg=ma`
`T-m(T)/(M)=(m+M)g`
`T=((m+M)Mg)/(M-m)=((30+60)60XX10)/(60-30)`
`= (""^(3)cancel(90)XX600)/(cancel(30))=1800N`


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