In the proscess Tprop W, pressure of the gas increase from p_(o) to t_(o) Match the columns. {:(,"ColumnI",, "ColumnII"),((A),"Temperature of teh gas",(p),"Pssitive"),((B),"Volume of the gas",(q),"Nagative"),((C),"work done by the gas",(r),"Two times"),((D),"Heat supplies to the gas",(s),"Cannot say anything"):}

In the proscess Tprop W, pressure of the gas increase from p_(o) to t_

1.	In the proscess Tprop W, pressure of the gas increase from p_(o) to t_(o) Match the columns. {:(,"ColumnI",, "ColumnII"),((A),"Temperature of teh gas",(p),"Pssitive"),((B),"Volume of the gas",(q),"Nagative"),((C),"work done by the gas",(r),"Two times"),((D),"Heat supplies to the gas",(s),"Cannot say anything"):}
Answer» Solution :`Tprop T/Vor Tprop1/(T//p)or T propsqrtP` p has become four times. Therefore. T has BECOMES two times or V will have become `1/2` times. Since V is decreasing, WORK done by the gas is negative. Further. T is increasing, hence `DeltaU` will be CONNOT SAY abour `DELTAQ.` negative and `DeltaU` is positive Hence, ew cannot say about `DeltaQ`