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In the quadrilateral DEFG a circle is inscribed touching quadrilateral at R, S, P, Q. If ES = 5 cm, PF = 7 cm, QG = 5 cm, DR = 4 cm; then perimeter of the quadrilateral is …………(A) 40 cm (B) 21 cm (C) 42 cm (D) 20 cm |
Answer» Correct option is (C) 42 cm \(\because\) Tangents from an outer point to a circle are of equal length. \(\therefore ER=ES=5\,cm,\) (Tangents of circle from point E & ES = 5 cm) \(SF=PF=7\,cm,\) (Tangents of circle from point F & PF = 7 cm) \(GP=QG=5\,cm\) (Tangents of circle from point G & QG = 5 cm) and \(QD=DR=4\,cm\) (Tangents of circle from point D & DR = 4 cm) \(\therefore\) Perimeter of quadrilateral DEFG \(=(DR+ER)+(ES+SF)\) \(+(PF+GP)+(QG+QD)\) \(=(4+5)+(5+7)+(7+5)+(5+4)\) \(=9+12+12+9\) \(=18+24=42\,cm\) Correct option is: (C) 42 cm |
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