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In the question 3, the ratio of conduction current and the displacement current isA. `((api)/(lamda))^(2)`B. `((a pi)/(lamda))`C. `((lamda)/(api))^(2)`D. `((lamda)/(2pi))` |
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Answer» Correct Answer - A The displacement current `I^(d)=intJ_(d)sdsd theta` `=(2pi)/(lambda^(2))I_(0)int_(theta=0)^(2pi)int_(s=0)^(a)ln.((a)/(s))sds sin(2piupsilont)d theta` `=((2pi)/(lambda))^(2)I_(0)int_(s=0)^(a)(1)/(2)ds^(2)ln((a)/(s))sin(2piupsilont)` `=(a^(2))/(4)((2pi)/(lambda))^(2)I_(0)int_(s=0)^(a)d((s)/(a))^(2)ln.((a)/(s))^(2)sin(2pi upsilont)` `=(a^(2))/(4)((2pi)/(lambda))^(2)I_(0)sin(2piupsilont)` `I^(d)=((api)/(lambda))^(2)I_(0)sin2pi upsilont=I_(0)^(d)sin2pi upsilontrArr(I_(0)^(d))/(I_(0))=((api)/(lambda))^(2)` |
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