InterviewSolution
Saved Bookmarks
| 1. |
In the question above instead of assuming ∠OAB = ∠OCD assuming that AB = CD and then prove that ∠OAB = ∠OCD. |
|
Answer» ∠OAB = ∠OCD (Given) OA = OC (radius). ∠P = ∠Q = 90° ∴ (OP ⊥ AB, OQ ⊥ CD ) ∴ ΔOAP ≅ ΔOCQ; ∴ OP = OQ, Therefore AB = CD [Equal chords of a circle are equidistant from die centre] |
|