1.

In the question above instead of assuming ∠OAB = ∠OCD assuming that AB = CD and then prove that ∠OAB = ∠OCD.

Answer»

∠OAB = ∠OCD (Given)

OA = OC (radius).

∠P = ∠Q = 90°

∴ (OP ⊥ AB, OQ ⊥ CD ) ∴ ΔOAP ≅ ΔOCQ;

∴ OP = OQ, Therefore AB = CD

[Equal chords of a circle are equidistant from die centre]



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