In the question number 1, the angle phi which the velocity vector of stone makes with horizontal just before hitting the ground is given by

In the question number 1, the angle phi which the velocity vector of s

1.	In the question number 1, the angle phi which the velocity vector of stone makes with horizontal just before hitting the ground is given by
Answer» `tan phi = 2 tan theta` `tan phi= 2 cot theta` `tan phi= SQRT(2) tan theta` `tan phi = sqrt(2) cot theta` Solution :Let `u_(y)andv_(y)` be initial and final vertical components of VELOCITY respectively. `:.u_(y)^(2)=2gHandv_(y)^(2)=4gH:.v_(y)=sqrt2u_(y)` Final velocity MAKES angle `(phi)`with horizontal. `:.tanphi=(v_(y))/(u_(X))=sqrt(2)(u_(y))/(u_(x))=sqrt(2)tantheta`