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In the question number 1, the angle `phi` which the velocity vector of stone makes with horizontal just before hitting the ground is given byA. `tan phi = 2 tan theta`B. `tan phi = 2 cot theta`C. `tan phi = sqrt(2) tan theta`D. `tan phi = sqrt(2) cot theta` |
Answer» Correct Answer - C Let `u_(y)andv_(y)` be initial and final vertical components of velocity respectively. `:.u_(y)^(2)=2gHandv_(y)^(2)=4gH:.v_(y)=sqrt2u_(y)` Final velocity makes angle `(phi)`with horizontal. `:.tanphi=(v_(y))/(u_(x))=sqrt(2)(u_(y))/(u_(x))=sqrt(2)tantheta` |
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