In the question number 11, the percentage strain produced in the rod i

1.	In the question number 11, the percentage strain produced in the rod is
Answer» Â 0.04% 0.0008 Â 0.16% Â 0.24 % Solution :Elongation, `DeltaL = ((F//A)L)/(Y) = ((3.18xx10^(8) N m^(-2))(1 m))/(2XX10^(11)N m^(-2))` `=1.59xx10^(-3) m = 1.59 mm` STRAIN produced in the rod is Strain `= (DeltaL)/(L) = (1.59 xx 10^(-3)m)/(1m) = 1.59xx10^(-3) = 0.16%`

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