In the question number 56, the maximum horizontal distance covered by

1.	In the question number 56, the maximum horizontal distance covered by the ball will be
Answer» `160sqrt(3)`m `140sqrt(3)` m `120sqrt(3)` m `100sqrt(3)` m Solution :Horizontal range, `R = (U^(2)sin2theta)/(G)` `R = ((56)^(2) SIN60^(@))/(9.8) = (56 xx 56 xxsqrt(3))/(9.8 xx 2) = 160sqrt(3)m`

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