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In the question number 56, the maximum horizontal distance covered by the ball will beA. `160sqrt(3)` mB. `140sqrt(3)` mC. `120sqrt(3)` mD. `100sqrt(3)` m |
Answer» Correct Answer - A Horizontal range, `R = (u^(2)sin 2theta)/(g)` `R = ((56)^(2) sin60^(@))/(9.8) = (56 xx 56 xxsqrt(3))/(9.8 xx 2) = 160sqrt(3)m` |
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