1.

In the question number 62. the maximum height attained by the ball is

Answer»

11.25 m
48.2 m
23. 5 m
68 m

SOLUTION :The maximum height is GIVEN by
`H=(u^(2)sin^(2)theta)/(2g)=((30)^(2)sin^(2)30^(@))/(2XX10)=11.25m`


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