1.

In the question number 62. the maximum height attained by the ball isA. 11.25 mB. 48.2 mC. 23. 5 mD. 68 m

Answer» Correct Answer - A
The maximum height is given by
`H=(u^(2)sin^(2)theta)/(2g)=((30)^(2)sin^(2)30^(@))/(2xx10)=11.25m`


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