In the question number 77, the force acting 011 thr particle is

1.	In the question number 77, the force acting 011 thr particle is
Answer» `momega^(2)overset(rightarrow)(r)` `-momega^(2)overset(rightarrow)(r)` `2momega^(2)overset(rightarrow)(r)` `-2momega^(2)overset(rightarrow)(r)` SOLUTION :`Given,: bar(r)=A COS omegahati+B sin omegathati` `"VELOCITY", bar(v)=(d barr)/(DT)=(d)/(dt)(A cosomegat hati+Bsin omegathatj)` `=-A omegasin omegahati+B omega cos omegahatj` `"Acceleration", bar(a)=(dbar(v))/(dt)=-Aomega^(2) cos omegat^(2)-Bomega^(2)sin omegathatj` The force acting on the particle is `bar(F)=mbar(a)=m(-omega^(2)bar(r))=-momega^(2)bar(r)`

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