1.

In the question number 89, the force of friction acting on the cylinder is

Answer»

2/3 Mg SIN`theta`
1/3 Mg sin`theta`
2/5 Mg sin`theta`
2/7 Mg sin`theta`

SOLUTION :FORCE of FRICTION, `f=Mgsintheta-Ma`
`=Mgsintheta-2/3Mgsintheta=1/3Mgsintheta`


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