In the question number 91, if a force Fis applied to 20 kg block, then the tension in the string is

In the question number 91, if a force Fis applied to 20 kg block, then

1.	In the question number 91, if a force Fis applied to 20 kg block, then the tension in the string is
Answer» <html><body><p>100N<br/><a href="https://interviewquestions.tuteehub.com/tag/200n-290170" style="font-weight:bold;" target="_blank" title="Click to know more about 200N">200N</a><br/>300N<br/>400N</p>Solution :<img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/NCERT_OBJ_FING_PHY_XI_C05_E01_092_S01.png" width="80%"/> <br/> When a force F is applied on 20kg block, then the <a href="https://interviewquestions.tuteehub.com/tag/tension-1241727" style="font-weight:bold;" target="_blank" title="Click to know more about TENSION">TENSION</a> in <a href="https://interviewquestions.tuteehub.com/tag/string-11290" style="font-weight:bold;" target="_blank" title="Click to know more about STRING">STRING</a> is T=m_(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)=(10kg)(20ms^(-<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>))=200N</body></html>