In the reactio, Fe(OH)_3(s) hArr Fe^(3+) (aq)+ 3OH^(-)(aq), if the concentration of OH^(-) ions is decreased by 1/4 times , then the equilibrium concentrationof Fe^(3+) will …………………………. .

In the reactio, Fe(OH)_3(s) hArr Fe^(3+) (aq)+ 3OH^(-)(aq), if the con

1.	In the reactio, Fe(OH)_3(s) hArr Fe^(3+) (aq)+ 3OH^(-)(aq), if the concentration of OH^(-) ions is decreased by 1/4 times , then the equilibrium concentrationof Fe^(3+) will …………………………. .
Answer» not CHANGED also decreased by `1/4` times increase by 4 times increase by 64 times Solution :`K_C = ([Fe^(3+)][OH^(-)]^3)/([Fe(OH)_3(s)]) = [Fe^(3+)][OH^(-)]^(-3)` [`:.` CONCENTRATION of solids is constant] When concentration of `OH^(-)` IONS decreased by `1/4` times,then `K_C = [Fe^(3+)]xx(([OH^(-)])/4)^3 = 1/64 [Fe^(3+)][OH^(-)]^3` To maintain `K_C` as constant, concentration of `Fe^(3+)` will increase by 64 times.