In the reaction 2AI(aq.) + 6HCI(aq.)→ 2AI3+ (aq.)+ 6CI (aq.) + 3H2

1.	In the reaction 2AI(aq.) + 6HCI(aq.)→ 2AI3+ (aq.)+ 6CI (aq.) + 3H2 (g)(a) 33.6 L H2 (g)is produced regardless of temperature and pressure for every mole of Al that reacts.(b) 67.2 L H2 (g) at NTP (0° C, 1 atm) is produced for every mole Al that reacts. (c) 11.2 L H2 (g) at NTP (0° C, 1 atm) is produced for every mole HCI(aq) consumed. (d) 6 L HCI(aq.) is consumed for every 3 L H2 (g)produced.
Answer» Correct option is : (c) Strategy : use the mole concept where moles of HCI are equated to the volume occupied by H₂ gas at N.T.P. as given by the balanced chemical equation. One mole of a gas at N.T.P. (0° C, 1 atm) occupies 22.4 L of volume. Solution : 6 moles of HCI liberate 3 moles of H₂ gas. Convert the moles of H₂ gas to the volume occupied by H₂ gas = 3 x 22.4 L of H₂ 6 moles of HCI liberate 3 x 22.4 L of H₂ 1 mole of HCI will liberate \(\frac{3\times 22.4}{6}=11.2L\)

In the reaction 2AI(aq.) + 6HCI(aq.)→ 2AI3+ (aq.)+ 6CI (aq.) + 3H2 (g)(a) 33.6 L H2 (g)is produced regardless of temperature and pressure for every mole of Al that reacts.(b) 67.2 L H2 (g) at NTP (0° C, 1 atm) is produced for every mole Al that reacts. (c) 11.2 L H2 (g) at NTP (0° C, 1 atm) is produced for every mole HCI(aq) consumed. (d) 6 L HCI(aq.) is consumed for every 3 L H2 (g)produced.

Answer»

Correct option is : (c)

Strategy : use the mole concept where moles of HCI are equated to the volume occupied by H₂ gas at N.T.P. as given by the balanced chemical equation.

One mole of a gas at N.T.P. (0° C, 1 atm) occupies 22.4 L of volume.

Solution : 6 moles of HCI liberate 3 moles of H₂ gas.

Convert the moles of H₂ gas to the volume occupied by H₂ gas = 3 x 22.4 L of H₂

6 moles of HCI liberate 3 x 22.4 L of H₂

1 mole of HCI will liberate \(\frac{3\times 22.4}{6}=11.2L\)