In the reaction ` 2K MnO_4 + 16 HCl rarr 5Cl_2 + 2MnCl_2 + 2 KCl+ 8H_2O` the reduced product is .A. `Cl_2`B. ` KCl`C. ` H_2O`D. `MnCl_2`

In the reaction ` 2K MnO_4 + 16 HCl rarr 5Cl_2 + 2MnCl_2 + 2 KCl+ 8H_2

1.	In the reaction ` 2K MnO_4 + 16 HCl rarr 5Cl_2 + 2MnCl_2 + 2 KCl+ 8H_2O` the reduced product is .A. `Cl_2`B. ` KCl`C. ` H_2O`D. `MnCl_2`
Answer» Correct Answer - D In the given redox reaction, ` KMnO_4` is reduced to `MnCl_2` while ` HCl` is oxidized to ` Cl_2`: `Koverset(+7)(M)nO_(4)+Hoverset(-1)(C)l rarr overset(0)(C)l_(2)+overset(+2)(M)nCl_(2)+KCl+H_(2)O` Thus, the reduced produce is `MnCl_2`.

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In the reaction ` 2K MnO_4 + 16 HCl rarr 5Cl_2 + 2MnCl_2 + 2 KCl+ 8H_2O` the reduced product is .A. `Cl_2`B. ` KCl`C. ` H_2O`D. `MnCl_2`

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