In the reaction 4A+2B+3CrarrA_(4)B_(2)C_(3), what will be the number of moles of product formed, starting from one mole of A, 0.6 moles of B and 0.72 moles of C

In the reaction 4A+2B+3CrarrA_(4)B_(2)C_(3), what will be the number o

1.	In the reaction 4A+2B+3CrarrA_(4)B_(2)C_(3), what will be the number of moles of product formed, starting from one mole of A, 0.6 moles of B and 0.72 moles of C
Answer» `0.25` `0.3` `0.24` `2.32` Solution :`4A+2B+3CrarrA_(4)B_(2)C_(3)` `(1)/(4),(0.6)/(2)(0.72)/(3)` `(0.72)/(3)lt(1)/(4)lt(0.6)/(2)` implies C is LIMITING reagent implies AMOUNTOF product = `(0.72)/(3)=0.24`