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In the reaction, `4NH_(3)(g)+5O_(2)(g) rarr 4NO(g)+6H_(2)O(g)`, when 1 mole of ammonia and 1 mole of `O_(2)` are made to react to completionA. (a)1.0 mole of H_(2)O is producedB. (b)1.0 mole of NO will be producedC. (c )All the oxygen will be consumedD. (d)All the ammonia will be consumed |
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Answer» Correct Answer - C `4NH_(3(g))+5O_(2(g))rarr 4NO_((g))+ 6H_(2)O_((g))` `t=0" "1" " 1" "0 " "0` `t=" "t" "1-4x" " 1-5x" "4x " " 6x` Oxygen is limiting reagent So, `X=1/5=0.2` all oxygen consumed Left `NH_(3)=1-4xx0.2=0.2.` |
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