1.

In the reaction, 4Zn + NO_(3)^(-) + 7H_(2)O rarr 4Zn^(2+) + NH_(4)^(+) + 10OH^(-), the substance which gets reduced is "______________".

Answer»

`Zn` is REDUCED to `Zn^(2+)`
`H_(2)O`
`NO_(3)^(-)`
`NH_(4)^(-)`

ANSWER :C


Discussion

No Comment Found