1.

In the reaction AB_(2)(l)+3X_(2)(g)hArrAX_(2)(g)+2BX_(2)(g) DeltaH=-2700 kcal per mole. Of AB_(2)(l). The entalpies of formation of AX_(2)(g) and BX_(2)(g) are in the ratio of 4 : 3 and have opposite sign. The value of DeltaH_(f)^(@)(AB_(2)(l))=30 kcal//mol. Then :

Answer»

`DeltaH_(f)^(@)(AX_(2))=-96kcal//mol`
`DeltaH_(f)^(@)(BX_(2))=+480kcal//mol`
`K_(p)=K_(C)` and `DeltaH_(f)^(@)(AX_(2))=+480kcal//mol`
`K_(p)=K_(c) " RT"` and `DeltaH_(f)^(@)(AX_(2))+DeltaH_(f)^(@)(BX_(2)=-240kcal//mol`

ANSWER :C


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