In the reaction between dilute nitric acid and magnesium metal, (a) how many moles of HNO_(3) reacts with a gram atom of metal? and (b) how many moles of HNO_(3) is oxidised by a gram atom of metal?

In the reaction between dilute nitric acid and magnesium metal, (a) ho

1.	In the reaction between dilute nitric acid and magnesium metal, (a) how many moles of HNO_(3) reacts with a gram atom of metal? and (b) how many moles of HNO_(3) is oxidised by a gram atom of metal?
Answer» Solution :The skeleton equation is `MG+HNO_(3) to Mg(NO_(3))_(2)+NH_(4)NO_(3)+H_(2)O` The BALANCED equation is `4Mg +10HNO_(3) to 4Mg(NO_(3))_(2)+NH_(4)NO_(3)+3H_(2)O` (a) NUMBER of MOLES of `HNO_(3)` that reacts with a gram atom of Mg=10/4=2.5 (b) `NO_(3)^(-)` is a spectator ion. It is NEGLECTED in the equation. `4Mg+NO_(3)^(-)+10H^(+) to 4Mg^(2+)+NH_(4)^(+)+3H_(O)` Number of moles of `HNO_(3)` that is reduced by a gram atom of Mg=0.25.