In the reaction, C_((s)) + CO_(2(g)) harr 2CO_((g)) the equilibrium pressure is 12 atm. If 50% of CO_(2) reacts, calculate K_(P). If K_(P)= y^(2) then what is 'y" ?

In the reaction, C_((s)) + CO_(2(g)) harr 2CO_((g)) the equilibrium pr

1.	In the reaction, C_((s)) + CO_(2(g)) harr 2CO_((g)) the equilibrium pressure is 12 atm. If 50% of CO_(2) reacts, calculate K_(P). If K_(P)= y^(2) then what is 'y" ?
Answer» <P> Solution : total PRESSURE = `(3P)/(2)=12 IMPLIES P=8` atm `:. K_(P)=((8)^(2))/((4))=4`