In the reaction `C(s)+CO_(2)(g) hArr 2CO(g)`, the equilibrium pressure is `12` atm. If `50%` of `CO_(2)` reacts, calculate `K_(p)`.

In the reaction `C(s)+CO_(2)(g) hArr 2CO(g)`, the equilibrium pressure

1.	In the reaction `C(s)+CO_(2)(g) hArr 2CO(g)`, the equilibrium pressure is `12` atm. If `50%` of `CO_(2)` reacts, calculate `K_(p)`.
Answer» Correct Answer - A `{:(,C(s),+,CO_(2),hArr,2CO(g)),("Gaseous moles",-,,1,,0),("before dissociation",,,,,),("Gaseous moles",-,,(1-50/100),,(2xx50)/100),("after dissociation",-,,0.5,,1):}` Total moles `=1.5` and `Deltan=1` Total pressure given at equilibrium `=12 "atm"` `K_(p)=((n_(CO))^(2))/((n_(CO_(2))))xx[P/(Sigman)]^(Sigma_(n)) ((1)^(2))/0.5xx(12/1.5)^(1)` `K_(p)=12/(1.5xx0.5)=16 "atm"`

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In the reaction `C(s)+CO_(2)(g) hArr 2CO(g)`, the equilibrium pressure is `12` atm. If `50%` of `CO_(2)` reacts, calculate `K_(p)`.

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