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In the reaction, `CH_(3)COOHoverset(L(A)H_(4))rarrAoverset(PC_(5))rarrBoverset(A//C.NOH)rarrC,` the product `C` is :-A. EthyleneB. Acetyl chlorideC. AcetaldehydeD. Acetylene |
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Answer» Correct Answer - A `CH_(3)-overset(O)overset(||)C-OHoverset(LiAIH_(4))rarrCH_(3)overset((A))-CH_(2)-OHoverset(PCl_(5))rarrCH_(3)overset((B))CH_(2)-Cloverset("alc"KOH)rarrCH_(2)overset((C))=CH_(2)` Reduction of `CH_(3)COOH` will produce `CH_(3)-CH_(2)-OH(A)` Now reaction of `CH_(3)-CH_(2)-OH(A)` with `PCl_(5)` will produce `CH_(3)-CH_(2)-Cl(B)`. Now alcoholic `KOH` with `Et-Cl` will produce `CH_(2)=CH_(2)(C)` Ethylene by `E_(2)` elemination. Thus Ans. is (1) Ethylene. |
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