In the reaction Fe(OH)_(3)(s)hArrFe^(3+)(aq)+3OH^(-)(aq), if the concentration of OH^(-) ions is decreased by 1/4 times, then the equilibrium concentration of Fe^(3+) will

In the reaction Fe(OH)_(3)(s)hArrFe^(3+)(aq)+3OH^(-)(aq), if the conce

1.	In the reaction Fe(OH)_(3)(s)hArrFe^(3+)(aq)+3OH^(-)(aq), if the concentration of OH^(-) ions is decreased by 1/4 times, then the equilibrium concentration of Fe^(3+) will
Answer» not changed also decreased by `1//4` time increase by 4 TIMES increase by 64 times Solution :`K_(C)=([Fe^(3+)][OH^(-)]^(3))/([Fe(OH)_(3)(s)])=[Fe^(3+)][OH^(-)]^(3)]` [`because` Concentration of solids is CONSTANT) When concentration of `OH^(-)` IONS decreased by `1.4` times, then `K_(C)=[Fe^(3+)]xx(([OH^(-)])/(4))^(3)=(1)/(64)[Fe^(3+)][OH^(-)]^(3)` To MAINTAIN `K_(C)` as constant, comcentration of `Fe^(3+)` will increase by 64 times.