

InterviewSolution
Saved Bookmarks
1. |
In the reaction given in euaqution 8, mention: I. Which reactant is oxidised? To what? II. Which reactant is the oxidiser? III.Which reactant is reduced? To what? IV. What reactant is the reducer? |
Answer» Correct Answer - A I. Zince metal is oxidised to (II) `Zn^(2+), Pb^(2+)` is the oxidiser. (III) `Pb^(2+)` is reduced to `Pb`,(IV) `Zn` is the reducer. b. `I^(ө)` is oxidised to `I_(2),Fe^(3+)` is oxidiser `Fe^(3+)` is reduced to `Fe^(2+), I^(-)` is the reducer. c. `Na` is oxidised to `na^(+), Cl_(2)` is the oxidiser. `Cl_(2)` is reduced to `Cl^(ө),Na` is the reducer. d. `Mg` is oxidised to `Mg^(+2), Cl_(2)` is the oxidiser. `Cl_(2)` is reduced to `Cl^(ө), Mg` is the reducer. e. `Zn` is oxidised to `Zn^(2+), H^(o+)` is the reducer. `H^(o+)` is reduced to `H_(2), Zn` is the reducer. |
|