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In the reaction. `H_(2)S+H_(2)O_(2) rarr S+2H_(2)O`A. `H_(2)S` is an and `H_(2)O_(2)` is a baseB. `H_(2)S` is a base and `H_(2)O_(2)` is an acidC. `H_(2)S` is an oxidizing agent and `H_(2)O_(2)` is a reducing agentD. `H_(2)S` is a reducing agent and `H_(2)O_(2)` is an oxidising agent |
Answer» Correct Answer - D Oxidation `underset("Reducing agent")overset(-2)(H_(2)S)+underset("-1 Oxidising agent ")(H_(2_(-))O_(2))underset("Reduction")rarroverset(0)(S)+underset(-2)(2H_(2_(-))O)` |
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