1.

In the reaction, `KMnO_(4) + 16 HCl rarr 5C1_(2) + 2MnCl_(2) + 2KCl + 8H_(2) O` the reduction product isA. `Cl_(2)`B. `MnCl_(2)`C. `H_(2)O`D. KCl

Answer» Correct Answer - B
In this reaction O.N of Mn changes from +7 in `KMnO_(4)` to +2 in `MnCl_(2)`. Thus, `MnCl_(2)` is the reduction product.


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